200=(1+x)^5

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Solution for 200=(1+x)^5 equation: 



200=(1+x)^5

We move all terms to the left:

200-((1+x)^5)=0

We add all the numbers together, and all the variables

-((x+1)^5)+200=0



We calculate terms in parentheses: -((x+1)^5), so:

(x+1)^5





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(x+1)^5





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(x+1)^5





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(x+1)^5





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(x+1)^5





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(x+1)^5





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(x+1)^5





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(x+1)^5





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(x+1)^5





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(x+1)^5





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We move all terms containing x to the left, all other terms to the right

-((x+1)^5)=-200

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